Author: Reinhard Scharnagl
Date: 03:46:33 03/03/05
Go up one level in this thread
Hi Dieter, There seems to be an elementar problem for me to count pieces, sorry! So I try again to calulate how many legal positions hould be possible on an 8x8 board with all pieces used. in each file there will be 15 possible valid pP configurations: 01: -p----P- 02: -p---P-- 03: -p--P--- 04: -p-P---- 05: -pP----- 06: --p---P- 07: --p--P-- 08: --p-P--- 09: --pP---- 10: ---p--P- 11: ---p-P-- 12: ---pP--- 13: ----p-P- 14: ----pP-- 15: -----pP- covering castling right could be reache by supporting three additional places for each king with the meaning: original place with left, right or double castling rights. placing all pawns: 15^8 placing white king + castling rights: 51 = (48+3) placing black king + castling rights: 50 = (47+3) placing white w Bishop in average: 23 placing white b Bishop in average: 23 placing black w Bishop in average: 22 placing black b Bishop in average: 22 placing 2 white Knights: 42*41/2 placing 2 black Knights: 40*39/2 placing 2 white Rooks: 38*37/2 placing 2 black Rooks: 36*35/2 placing white Queen: 34 placing black Queen: 33 side to move 2 e.p. is possible or not 2 affected e.p. file 8 -------------------------------------------- estimated possibilities 51*50*(2^3)*(23^2)*(11^2)*(15^8)*42!/32! this is meaning about 113.78 bits. Reinhard.
This page took 0 seconds to execute
Last modified: Thu, 15 Apr 21 08:11:13 -0700
Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.