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Subject: Re: Computational question for mathematicians, philosophers & computer-geeks

Author: Reinhard Scharnagl

Date: 04:17:44 03/03/05

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Hi Dieter,


again I try again to calulate how many legal positions could be possible
on an 8x8 board with all pieces used.

in each file there will be 15 possible valid pP configurations:

01: -p----P-
02: -p---P--
03: -p--P---
04: -p-P----
05: -pP-----
06: --p---P-
07: --p--P--
08: --p-P---
09: --pP----
10: ---p--P-
11: ---p-P--
12: ---pP---
13: ----p-P-
14: ----pP--
15: -----pP-

covering castling rights could be reached by supporting three additional
places for each king with the meaning: original place with left, right
or double castling rights.

placing all pawns:                     15^8
placing white king + castling rights:  51 = (48+3)
placing black king + castling rights:  50 = (47+3)
placing two white Bishops at worst:    23*23
placing two black Bishops at worst:    22*22
placing 2 white Knights:               42*41/2
placing 2 black Knights:               40*39/2
placing 2 white Rooks:                 38*37/2
placing 2 black Rooks:                 36*35/2
placing white Queen:                   34
placing black Queen:                   33
side to move                           2
affected e.p. file or none             9
--------------------------------------------
estimated possibilities                51*25*9*(23^2)*(11^2)*(15^8)*42!/*32!

this is meaning about 112.95 bits.

Reinhard.




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