Author: Dann Corbit
Date: 19:09:40 03/03/05
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On March 03, 2005 at 20:36:21, Rob Basham wrote: >[D]2r5/p4p2/1p3Nk1/4Q3/8/P7/5PPP/3R2K1 w - - 0 1 > >there is a mate in 6 > >Five different mates in 7 > >a mate in 8 >and a mate in 9 > >and maybe more solutions...! >:-) > >rob There are two mates in 5, Ng4 and Nh5. The trajectory for Ng4 is given in the pv: 2r5/p4p2/1p3Nk1/4Q3/8/P7/5PPP/3R2K1 w - - acn 585269; acs 1; bm Ng4 Nh5; ce 32758; dm 5; pv Ng4 Rd8 Qf6+ Kh5 Qf5+ Kh4 g3+ Kh3 Ne5#;
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