Author: Ricardo Gibert
Date: 21:12:33 07/01/05
Go up one level in this thread
> >Just about any line will result in White having a Rook, a Bishop/Knight, and two >Pawns, against Black with a Rook and two Pawns. > >One line results in the Rooks being traded off as well, and it appears that this >one does win, but Black can avoid it. > >38...Ke7 39.g7 Rg3 40.Re8+ Kd6 41.Ne3 Rcxg7 42.Nf5+ Kd7 43.Nxg7 Rxg7 >44.Bxg7 Kxe8 > >Here are several possible positions that Black can steer the game to: I'll take on the first 2 and if you still think the other 2 are still viable, I can do them too if you wish. > >[D]R7/4k3/p1r5/1p6/1P4N1/1K6/P7/8 w - - 0 7 1.Ne5 Rd6 2.Kc3 Re6 3.Nd3 Rh6 4.a3 Rg6 5.Nc5 Rg3+ 6.Kb2 +- > >[D]R7/2k5/p5r1/1p6/1P6/1KB5/P7/8 w - - 0 4 1.Ra7+ Kc8 2.Bd4 Rg3+ 3.Kc2 Rg2+ 4.Kb1 Rg6 5.Bc5 Rh6 6.a3 Rf6 7.Kc2 Rg6 8.Kd2 Rh6 9.Kd3 Rg6 10.Ke4 Rf6 11.Kd5 Kb8 12.Re7 Rg6 13.Re6 +- > >[D]6R1/2r1k3/p7/1p6/1P6/1KB5/P7/8 b - - 0 4 > >[D]4R3/8/p2k4/1p6/1P4N1/1K6/P1r5/8 b - - 0 8 > >Are you guaranteeing that there is some line in which White will be able to >force the win of a pawn? If Black can force the trade of both Pawns, it's a >draw. I'm not saying that you're wrong, but I'd love to see you prove that >you're right. :-) > >jm
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