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Subject: Re:haha,FRC openings?

Author: Günther Simon

Date: 07:54:03 07/08/05

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On July 08, 2005 at 10:19:58, Madhavan wrote:

>On July 07, 2005 at 20:47:33, Jorge Pichard wrote:
>
>>Since the standard chess Opening is one of the 960 Fischer Random Positions, and
>>there are many Standard chess openings, could we simply determine the amount of
>>possible Chess960 openings by multiplying the amount of chess opening in the
>>standard chess position by 960, or the process in much more complicated than
>>that?
>>
>>Jorge
>
>you don't know what you are talking about
>
>how could you possibly make such an assumption?I don't know if you could even
>remember how to arrange all 960 different position,thats the initial step,and
>there you go on talking about openings in FRC,that's hilarious.
>
>:)



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