Author: Günther Simon
Date: 07:56:32 07/08/05
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On July 08, 2005 at 10:19:58, Madhavan wrote: >On July 07, 2005 at 20:47:33, Jorge Pichard wrote: > >>Since the standard chess Opening is one of the 960 Fischer Random Positions, and >>there are many Standard chess openings, could we simply determine the amount of >>possible Chess960 openings by multiplying the amount of chess opening in the >>standard chess position by 960, or the process in much more complicated than >>that? >> >>Jorge > >you don't know what you are talking about > >how could you possibly make such an assumption?I don't know if you could even >remember how to arrange all 960 different position,thats the initial step,and >there you go on talking about openings in FRC,that's hilarious. > >:)
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