Author: Jorge Pichard
Date: 12:43:55 07/08/05
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On July 08, 2005 at 15:43:05, Jorge Pichard wrote: >On July 08, 2005 at 10:19:58, Madhavan wrote: > >>On July 07, 2005 at 20:47:33, Jorge Pichard wrote: >> >>>Since the standard chess Opening is one of the 960 Fischer Random Positions, and >>>there are many Standard chess openings, could we simply determine the amount of >>>possible Chess960 openings by multiplying the amount of chess opening in the >>>standard chess position by 960, or the process in much more complicated than >>>that? >>> >>>Jorge >> >>you don't know what you are talking about >> >>how could you possibly make such an assumption?I don't know if you could even >>remember how to arrange all 960 different position, > >I don't want to waste time with you, but nobody has to know the initial 960 >positions, you simply have to download it and use it with any FRC engine. > >initial 960 positions: http://www.chesstigers.de/download/chess960_regeln.pdf > >PS: That was not the question, and I don't think that you are capable of >answering it correctly anyway. Apparently you didn't understand the question. > >Jorge > >thats the initial step,and >>there you go on talking about openings in FRC,that's hilarious. >> >>:)
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