Author: Günther Simon
Date: 03:44:18 07/09/05
Go up one level in this thread
On July 09, 2005 at 06:24:59, Madhavan wrote: >On July 09, 2005 at 05:11:58, Jorge Pichard wrote: > >>On July 09, 2005 at 00:49:51, Madhavan wrote: >> >>>On July 08, 2005 at 15:43:05, Jorge Pichard wrote: >>> >>>>On July 08, 2005 at 10:19:58, Madhavan wrote: >>>> >>>>>On July 07, 2005 at 20:47:33, Jorge Pichard wrote: >>>>> >>>>>>Since the standard chess Opening is one of the 960 Fischer Random Positions, and >>>>>>there are many Standard chess openings, could we simply determine the amount of >>>>>>possible Chess960 openings by multiplying the amount of chess opening in the >>>>>>standard chess position by 960, or the process in much more complicated than >>>>>>that? >>>>>> >>>>>>Jorge >>>>> >>>>>you don't know what you are talking about >>>>> >>>>>how could you possibly make such an assumption?I don't know if you could even >>>>>remember how to arrange all 960 different position, >>>> >>>>I don't want to waste time with you, but nobody has to know the initail 960 >>>>positions, you simply have to download it and use it with any FRC engine. >>> >>>yeah,waste your time with FRC,you haven't got anyone's attention,get it? >>> >>>>initial 960 positions: http://www.chesstigers.de/download/chess960_regeln.pdf >>>> >>>>PS: That was not the question, and I don't think that you are capable of >>>>answering it correctly anyway. Apparently you didn't understand the question. >>> >>>In the first place,you should be knowing how to arrange initial position.there >>>you went on talking about amount of position in FRC by multiplying the amount of >>>openings in standard,which is not true. >>> >> >>If you read carefully, what I meant to say is, that since the standard chess >>position is one of the position counted as part of the 960 FRC positions, for >>the rest of the 959 positions which make a total of 960, all you have to do is >>multiply the amount of openings in standard chess by 960, and it will give us an >>average amount of openings that we could possibly get in FRC; by creating huge >>databases of games played by good programs such as Hiarcs-FRC or Shredder-FRC. > >I understand your original message,do you get this "959 position deffers in >amount of opening than that 1 standard opening" >Let's say there are about 200 openings in standard opening,this doesnt mean >there are also 200 opening in 959 position. > >In the first place if you were talking about human chess,you just can't remember >959 position yourself,if this comes to comp chess,refer the above. It is completely independent from computer or Human chess, it's just about chess. It is also completely independent from someone memorizing all theory. I don't know what is so difficult to understand about? No one needs to know, neither knows _all_ opening theory in standard chess, yet it exists, same will will be true for FRC with 959 start positions more. It is just a scientific question of how much bigger opening theory for FRC might be in the future... Guenther
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