Author: Rémi Coulom
Date: 03:37:34 02/18/99
Go up one level in this thread
On February 18, 1999 at 06:32:12, Rémi Coulom wrote: >I just calculated the probability to have two identical values in a list of p >values chosen at random among q possible values. Maybe everybody knew this >already, but I was ignorant of the result and I find it is interesting. The >result is, for large values of q and p < q, equivalent to exp(-(p*p)/(2*q)). It Sorry, the result is 1 - exp(-(p*p)/(2*q))
This page took 0.01 seconds to execute
Last modified: Thu, 15 Apr 21 08:11:13 -0700
Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.