Author: Gabor Szots
Date: 11:54:54 08/29/05
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On August 29, 2005 at 14:51:21, Robert Hyatt wrote: >Just noticed something strange. Crafty and Junior finished with scores of 6.5, >which would (should) mean we tied for places 5/6. But somehow the final >crosstable has crafty 5th and Junior 6th. The "SB" tiebreak somehow favors >Crafty. I'm not sure how this is computed, but in a RR, it would seem that >tiebreaks are pointless unless it somehow factors in that we had 6 blacks, or >that we had black against stronger opponents and white against weaker opponents, >or whatever. > >Anyone care to enlighten me on how that particular tiebreak works? I notice >that Sjeng and Shredder are listed as tied for 3/4, with the same SB scores... > >Would seem more reasonable that Crafty/Junior are listed as tied for 5/6... SB is computed as follows: You get all the points of the opponents you defeated and half the points of the opponents against whom you made a draw. Gábor
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