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Subject: Re: Crafty book question.

Author: Kevin K

Date: 16:39:56 09/03/05

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On September 03, 2005 at 18:11:23, A. Cozzie wrote:

>On September 03, 2005 at 18:06:05, Robert Hyatt wrote:
>
>>On September 03, 2005 at 17:05:36, Kevin K wrote:
>>
>>>Hello, Dr. Hyatt.
>>>
>>>1 d2-d4 d7-d5  2 e2-d4
>>>1 e2-d4 d7-d5  2 d2-d4
>>>
>>>These two moves are considered the same in transposition table,
>>>because resulting positions are the same.
>>>But, what about in book database?
>>>As far as I know, Crafty does not consider these the same positions in book.
>>>Why not?
>>>For example, if I have only 1 d2-d4 d7-d5  2 e2-d4 e7-e6 in book and
>>>if I play 1 e2-d4 d7-d5  2 d2-d4, Crafty does not find next move(e7-e6)
>>>from book even though two positions are the same.
>>>
>>>Thank you.
>>
>>
>>A book position is based on the parent position and the child position.  That
>>is, the position before the move and the position after the book.
>>
>>This was done to avoid a well-known transposition "bug"..
>
>Probably not well known to him, Bob :)
>
>If you do the book purely based on position you can get problems like this
>example (the program being black)
>
>1. e4 e5 2. Bb5 a6 3 Nf3 Nc6??
>
>anthony

I know what you mean. But,
1. e4 e5  2. Nf3 Nc6  3 Bb5  and
1. e4 e5  2. Bb5 a6   3.Nf3 are different positions.
Positions just before final position must be the same.
This doesn't seem good example.



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