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Subject: Re: mask of highest bit - additional notes

Author: Mridul Muralidharan

Date: 10:28:15 09/22/05

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On September 22, 2005 at 12:35:50, Andrew Shapira wrote:

>"There is no way to do that" is a pretty strong statement.  Where's the proof?
>
>On September 22, 2005 at 03:47:58, Gerd Isenberg wrote:
>
>>On September 22, 2005 at 02:40:22, Andrew Shapira wrote:
>>
>>>Yeah, I know about http://graphics.stanford.edu/~seander/bithacks.html
>>> - I have used it and some other web sites extensively.  I have racked my brains
>>>for 2 days, on the couch, in the shower, in bed, while walking around, and still
>>>haven't figured it out.  My sense is that it seems doable, and that a solution
>>>could involve subtracting x from (2^n)-1.  This might be a high-order analog of
>>>the x-1 term that occurs in the expression x^(x-1) that comes up in low-order
>>>bit computations.
>>
>>Nope, to answer your original question again, hopefully more clearly.
>>There is no cheap way with the operators you mentioned to mask MS1B.
>>The LS1B tricks works due to two's complement, or one's complement plus one.
>>It has something to do with carry propagation which unfortunately only works in
>>one direction as we don't have reverse arithmetic ;-)
>>
>>Gerd

Two things -
1) The quotes statement is wrong : "easy" was missed.
2) He was trying to help : cant demand , only request

- Mridul



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