Author: Dann Corbit
Date: 12:13:22 11/08/05
Go up one level in this thread
On November 08, 2005 at 14:11:12, Vincent Lejeune wrote: > >I made 2 mistakes : >Here is the key for this one : > >8/8/4kpp1/3p1b2/p6P/2B5/6P1/6K1 b - - c0 "Hardest"; >Bh3! > >Topalov,V (2740) - Shirov,A (2710) [D85] >Linares 15th Linares (10), 04.03.1998 >Ftacnik : > 47...Bh3!! Fascinating idea of Shirov, since black has to push his two pawns >a4,d5 as quickly as possible. The bishop would obstruct the way of the king on >the natural square e4, on h3 it wins a precious tempo. [ 47...a3 48.Kf2 a2 >49.Ke3 Bg4 50.g3 Kf5 51.Bd4÷; > 47...Be4 Shirov -+ 48.Kf2 Kf5 49.g3÷] 48.gxh3 [ 48.Kf2 Kf5 49.Kf3 Bxg2+ 50.Kxg2 >Ke4 51.Bxf6 d4 52.Be7 Kd3 53.Kf2 Kc2 54.Bb4 d3-+] 48...Kf5 49.Kf2 Ke4 50.Bxf6 [ >50.Ke2 a3 51.Kd2 d4 52.Ba1 f5-+] 50...d4 51.Be7 [ 51.Ke2? a3-+] 51...Kd3! 52.Bc5 >Kc4 53.Be7 [ 53.Bxd4 Kxd4 54.Ke2 Kc3 55.Kd1 Kb2-+] 53...Kb3 [ 53...Kb3 54.Bc5 d3 >55.Ke3 Kc2 56.Bb4 a3-+] 0-1 > >and for this one : >1r3rk1/3b1p1p/pp1p1p1Q/n1q1p3/2P1P3/P1PB1N2/6PP/1R3RK1 w - - bm Nd4; >Only Nd4 is possible because king is in check. > >Thanks for testing , Dann ! > >On November 08, 2005 at 13:31:38, Dann Corbit wrote: > >>b2r3r/4Rp1p/p2q1np1/1p1P4/kP1Q4/P4PPB/2P4P/1K6 w - - bm Ra7; >>r3r1k1/1p3pp1/p1bp1b1B/2q1n3/2PN4/1P5P/2BR1QP1/5RK1 w - - bm b4; >>4RQ2/5p2/2q2kp1/3p4/3P2PP/8/1K6/8 b - - c0 "Draw"; >>8/3P3k/n2K3p/2p3n1/1b4N1/2p1p1P1/8/3B4 w - - bm Nf6+; >>rnb2rk1/pp2bppp/2p5/q7/4NN2/4B1QP/PPP3P1/2KR3R w - - bm Rd5; >>r3k2r/4b2p/p1n3pN/1p1q1p2/5B2/3p1P2/PP4PP/2RQR2K w kq - bm Rxc6; >>1r3rk1/3b1p1p/pp1p1p1Q/n1q1p3/2P1P3/P1PB1N2/6PP/1R3RK1 w - - bm Nd4 Nh4; >>1r6/4k3/r2p2p1/2pR1p1p/2P1pP1P/pPK1P1P1/P7/1B6 b - - id Brzozka - Bronstein; >>bm b8b3; >>8/8/4kpp1/3p1b2/p6P/2B5/6P1/6K1 b - - c0 "Hardest"; >>r1b2r1k/4qp1p/p2ppb1Q/4nP2/1p1NP3/2N5/PPP4P/2KR1BR1 w - - id "Kholmov - >>Bronstein"; bm d4c6; >>rqb1rnk1/4n1pp/2p5/2PpPpPP/1p3N2/1P1BP3/1BQ5/1K4RR w - - id "Bischoff - >>Nogueiras"; bm e5e6; >>r2q1rk1/pp2bpp1/4p2p/2pPB2P/2P3n1/3Q2N1/PP3PP1/2KR3R w - - id "Karpov - >>Huebner"; bm e5g7; >>r2q1rk1/3nbpp1/4p2p/p1p1P3/1p1P3P/3B1b1R/PPQB1PP1/R3K3 w Q - id "Portisch - >>Johannessen"; bm d2h6; >>... This one seems to be the same idea as WAC.230 (sac a rook to get a passed pawn, else the wall is impenetrable: [D]1r6/4k3/r2p2p1/2pR1p1p/2P1pP1P/pPK1P1P1/P7/1B6 b - - id Brzozka - Bronstein; bm b8b3; Since many programs can solve WAC.230 now, I am surprised that none of them can see the solution to this problem. Are you sure that the rook is compensated?
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