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Subject: Re: Christmas Tree Problem

Author: John Merlino

Date: 17:49:48 12/24/05

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On December 24, 2005 at 20:30:05, Alessandro Scotti wrote:

>On December 24, 2005 at 20:14:19, Mark Ryan wrote:
>
>>http://www2.forthnet.gr/chess/xmasmil.html
>>
>>I do NOT know the answer.
>
>[D]8/3p4/3p4/2pPp3/1pPkPp2/1n1p1n2/P2p2P1/3K4 b - - - -
>
>Kiwi can't see it either...
>
> 3/ 9  +7.92  00:00       524  Ng5 axb3 Nxe4
> 4/ 4  +7.92  00:00       579  Ng5 axb3 Nxe4 g3
> 5/ 5  +9.44  00:00      3290  Ng5 axb3 Nxe4 g3 fxg3
> 6/ 7  +9.52  00:00      3998  Ng5 a3 Nxe4
> 7/21     M4  00:00    114504  Ng5 g3 Nh3 axb3 Kc3

It's a sort of trick question, but there is still a flaw in it.

Unless I'm missing something, for it to be a Mate in 2 for Black White's last
move had to have been either c2-c4 or e2-e4. After EITHER of these moves, Black
capturing en passant leads to a Mate in 2.

However, the designation on the page "there is a single answer" is not correct,
because White could have made either of those moves, and therefore there are two
possible responses by Black.

jm



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