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Subject: Re: Christmas Tree Problem

Author: Sune Larsson

Date: 00:03:00 12/25/05

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On December 25, 2005 at 02:43:23, John Merlino wrote:

>On December 25, 2005 at 02:32:15, Uri Blass wrote:
>
>>On December 25, 2005 at 02:24:19, Sune Larsson wrote:
>>
>>>On December 24, 2005 at 20:49:48, John Merlino wrote:
>>>
>>>>On December 24, 2005 at 20:30:05, Alessandro Scotti wrote:
>>>>
>>>>>On December 24, 2005 at 20:14:19, Mark Ryan wrote:
>>>>>
>>>>>>http://www2.forthnet.gr/chess/xmasmil.html
>>>>>>
>>>>>>I do NOT know the answer.
>>>>>
>>>>>[D]8/3p4/3p4/2pPp3/1pPkPp2/1n1p1n2/P2p2P1/3K4 b - - - -
>>>>>
>>>>>Kiwi can't see it either...
>>>>>
>>>>> 3/ 9  +7.92  00:00       524  Ng5 axb3 Nxe4
>>>>> 4/ 4  +7.92  00:00       579  Ng5 axb3 Nxe4 g3
>>>>> 5/ 5  +9.44  00:00      3290  Ng5 axb3 Nxe4 g3 fxg3
>>>>> 6/ 7  +9.52  00:00      3998  Ng5 a3 Nxe4
>>>>> 7/21     M4  00:00    114504  Ng5 g3 Nh3 axb3 Kc3
>>>>
>>>>It's a sort of trick question, but there is still a flaw in it.
>>>>
>>>>Unless I'm missing something, for it to be a Mate in 2 for Black White's last
>>>>move had to have been either c2-c4 or e2-e4. After EITHER of these moves, Black
>>>>capturing en passant leads to a Mate in 2.
>>>>
>>>>However, the designation on the page "there is a single answer" is not correct,
>>>>because White could have made either of those moves, and therefore there are two
>>>>possible responses by Black.
>>>>
>>>>jm
>>>
>>>
>>> I'm not following you here. How, in the name of all Houdinis, could the
>>> last white move be e2-e4???
>>>
>>> /S
>>
>>I decided to post the solution after the hint that you give and after
>>understanding that the site is very old site and there is no point in keeping
>>the solution as a secret.
>>
>>Of course it cannot be e2-e4 because it means that the white bishop at f1 was
>>not captured by a pawn and the position is illegal because black needs too many
>>captures to get the pawn structure.
>>
>>
>>Uri
>
>Indeed, very impressive.
>
>I found a complete description of the solution (although the board is flipped
>such that it is WHITE to Mate in 2) here:
>
>www.gtryfon.demon.co.uk/bcc/news/dec98news.htm#Christmas%20tree%20puzzle!
>
>Fun problem!
>
>jm


 Yes, and if you think like children do - you'll see in an instant that e2-e4
 couldn't have been white's last move. If the pawn was on e2 - then Bf1 would
 never ever gotten out. That's why the Houdini hint ;-)

 /S



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