Author: Paulo Soares
Date: 14:26:51 04/05/99
Go up one level in this thread
On April 05, 1999 at 11:12:40, Steve Lopez wrote: >On April 05, 1999 at 02:12:06, Paulo Soares wrote: > >>The equation below is used to calculate the minimum hashtables size, >>and it is in the manual of Fritz5. I believe that it serves for the >>CM6000. > >[snip] > >The formula I use for Fritz is as follows. > >I assume a 50-move game. Approximately ten moves will likely be from the opening >book. So I divide the sudden death control (in minutes) by 40 (the number of >moves), and multiply the resulting number by 60 (to get the average number of >seconds per move). I then plug this number into the formula in the Fritz manual. I agree to you, is interesting esteem a number of moves for the opening, that is made in much less time that the others moves. I go to start to make that. Paulo Soares
This page took 0 seconds to execute
Last modified: Thu, 15 Apr 21 08:11:13 -0700
Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.