Author: Paulo Soares
Date: 15:39:02 04/05/99
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On April 05, 1999 at 17:46:18, blass uri wrote: > >On April 05, 1999 at 09:34:57, Micheal Cummings wrote: > >> >>On April 05, 1999 at 02:12:06, Paulo Soares wrote: >> >>>On April 05, 1999 at 00:48:11, Terry Ripple wrote: >>> >>>> If 16mb is more than enough for 40/2hr, then how much Hash Table Size would be >>>>enough for playing Sudden Death Games of 60/S.D.,30/S.D.,15/S.D. and 5/S.D. >>>> >>>> Would it be better to use smaller Hash Tables for these Sudden Death Games and >>>>if so, then what would be the best size to use? >>> >>>Terry, >>> Paulo Soares >>>The equation below is used to calculate the minimum hashtables size, >>>and it is in the manual of Fritz5. I believe that it serves for the >>>CM6000. >>> >>> HT(Kb)=2.0*Pfreq(Mgz)*t(S) >>> >>> HT= hashtable size in Kb. >>> Pfreq= clock speed of the processor in Mgz. >>> t= average time avaiable per move in seconds. >>> >>>Examples: >>>1. Processor with 200Mgz >>> Control time=40/2- Average time 3min=180s >>> >>> HT=2.0*200*180=72000Kb= 72Mb >>> >>>2. Processor with 200Mgz >>> Control time= Blitz(5min)- Average time=10s(esteemed) >>> >>> HT=2.0*200*10=4000Kb= 4Mb >>> >>>3. Processor with 400 Mgz >>> Control time= 40/1- Average time=1.5min=90s >>> >>> HT=2.0*400*90=90000Kb= 90Mb >>> >>>The program, in some moves, will spend a bigger time than the average >>>time, then I think that is always good to use a bigger hastable than >>>the calculated for the equation above. >>> >>>Best regards, >>>Paulo Soares, from Brazil. >> >> >>Well Johann suggest that a hash table of no bigger than 16meg should be used for >>CM6K. So I think you equation is off in the case of CM6K. I would not even >>consider using a 90 hash table even on my PII 450. > >I think that he said it only for pentium200MMX >and i f this is the case maybe a similiar formula can be for chessmaster but you >should multiply the optimal hash of Fritz by 16/72 so you get for >Processor with 200Mgz > >Control time=40/2- Average time 3min=180s > >HT=2.0*200*180*16/72=16000K=16Mb > >Uri Uri, Why to multiply by 16/72? I don't understand. Paulo Soares
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