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Subject: Re: Question about Fritz-Polgar

Author: James Swafford

Date: 20:26:56 04/30/99

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On April 30, 1999 at 21:13:22, James Robertson wrote:

>I have heard that the games were game in 60 and game 30, and Fritz won
>convincingly 5.5 - 2.5. But I have a question; what was the distrobution of the
>draws and wins over the time controls?
>
>On the official webpage they have this:
>
>
>              ápr. 27.  ápr. 28.  ápr. 29. ápr. 30.
>Polgár--Fritz
>14oo-16oo     0.5--0.5  0.5--0.5  0--1     1--0
>Fritz--Polgár
>16oo-17oo     0.5--0.5  1--0      1--0     1--0
>
>I may be misreading this but: the upper row is the scores for game in 60
>(because two hours of time was allocated), and the lower row game in 30 (because
>only one hour was allocated).
>
>If this is the case, then Polgar actually drew Fritz at game in 60!
>Which means that Polgar lost .5 - 3.5 at game in 30.
>
>Now then if Polgar loses .5 - 3.5 at G/30, and in double the amount of time,
>G/60, she draws 2 - 2, then the simplest logic tells us that in double G/60, or
>40/2 tournament time) then Polgar will defeat Fritz 3.5 - .5!!!
>
>James

What makes you think the w/l ratio will increase linearly?

--
James




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