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Subject: Re: Question about Fritz-Polgar

Author: James Robertson

Date: 20:35:12 04/30/99

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On April 30, 1999 at 23:26:56, James Swafford wrote:

>On April 30, 1999 at 21:13:22, James Robertson wrote:
>
>>I have heard that the games were game in 60 and game 30, and Fritz won
>>convincingly 5.5 - 2.5. But I have a question; what was the distrobution of the
>>draws and wins over the time controls?
>>
>>On the official webpage they have this:
>>
>>
>>              ápr. 27.  ápr. 28.  ápr. 29. ápr. 30.
>>Polgár--Fritz
>>14oo-16oo     0.5--0.5  0.5--0.5  0--1     1--0
>>Fritz--Polgár
>>16oo-17oo     0.5--0.5  1--0      1--0     1--0
>>
>>I may be misreading this but: the upper row is the scores for game in 60
>>(because two hours of time was allocated), and the lower row game in 30 (because
>>only one hour was allocated).
>>
>>If this is the case, then Polgar actually drew Fritz at game in 60!
>>Which means that Polgar lost .5 - 3.5 at game in 30.
>>
>>Now then if Polgar loses .5 - 3.5 at G/30, and in double the amount of time,
>>G/60, she draws 2 - 2, then the simplest logic tells us that in double G/60, or
>>40/2 tournament time) then Polgar will defeat Fritz 3.5 - .5!!!
>>
>>James
>
>What makes you think the w/l ratio will increase linearly?
>
>--
>James

Something nobody realized is that I'm joking. :( Of course I don't believe that.
:)

But it did seem the logical followup to defy my being silenced as another post
claimed I would be. :)

James



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