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Subject: Polgar and Fritz **TPR** Where does the 141 come from?

Author: Mark

Date: 08:14:00 05/05/99

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On May 05, 1999 at 06:42:18, blass uri wrote:

>
>On May 05, 1999 at 04:34:41, Harald Faber wrote:
>
>>On May 05, 1999 at 03:10:10, blass uri wrote:
>>
>>>>>>The Week in Chess gives what looks to be a mistake in Polgar's TPR for the Fritz
>>>>>>match.  Does anyone know the actual calculations used to determine TPR's???
>>>>>>
>>>>>>
>>>>>>Fritz 5.32   ----    =   =   =   1   1   1   0   1   5.5    **2818**
>>>>>>
>>>>>>Polgar, Judit  g HUN 2677    =   =   =   0   0   0   1   0   2.5    **1859**
>>>>>>(?)
>>>>>
>>>>>As we can count Fritz made a +141 elo performance ...
>>>>>we can deduce that J polgar made a -141 elo performance ...
>>>>>So Fritz have a 'default' rating of 2000 (Obviously the minimum for the
>>>>>performance calculating program)
>>>>
>>>>So there must be s.th. wrong because Polgar had a rating of 2677 (see above)
>>>>which would give 2677-141=2536TPR and Fritz 2000+141=2141TPR
>>>
>>>Fritz5.32's performance is 2677+141=2818
>>>Judit polgar's performance is 2000-141=1859
>>
>>Can you tell me where you get the 2000 for Polgar from? It is neither default
>>nor written above. Above it is 2677.
>
>The 2000 is for Fritz5 and not for polgar.
>
>Polgar's rating is not important when we compute polgar's performance.
>The only important thing is that polgar lost to unrated player 5.5:2.5
>
>Everyone who lose against stupid 2000 player 5.5:2.5 has performance
>2000-141=1859
>
>everything is right except the assumption that Fritz has 2000
>
>Uri


All you guys are great, thanks for the information.  My final question is where
does the 141 come from?  Here in the US you can get a provisional estimated
rating by taking, say, 6 games, adding 400 to your opponents rating if you win,
subtracting 400 if you lose, and no change if you draw.  Add those six figures
up and divide by 6 and viola!  Your provisional estimated rating.

Is this general procedure (with possible minor modifications) how the value 141
is calculated in the above discussion?  If it is, then by solving for X (instead
of using 400) I get 376, which is indeed a minor moditication to bring my
calculations in line with the 141 number.

Thanks for your replies!  Can't wait for HIARCS Yermolinsky!

Mark



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