Author: José de Jesús García Ruvalcaba
Date: 08:59:48 05/19/99
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On May 19, 1999 at 11:55:50, José de Jesús García Ruvalcaba wrote: >On May 19, 1999 at 11:32:51, Heiner Marxen wrote: > >>On May 18, 1999 at 08:02:09, Peter Klausler wrote: >> >>>On May 17, 1999 at 21:15:59, Dann Corbit wrote: >>> >>>>You would also need to store e.p. square, if any, I think. Ten bits more >>>>[5ep+4castle+1stm]gives 174 bits. >>> >>>Two bits are all you need for the en passant file, actually. >>>There can be at most four pawns of the opponent on his >>>fourth rank next to a pawn of the player (on his fifth). >> >>Wrong. There can be 5 such pawns. E.g. 8/8/8/8/PpPPpPPp/8/8/8 b - >>Even when we know already that there is an e.p. possible, we still >>have to distinguish up to at least 5 cases. > > Your position has five pawns on the fifth rank next to three of the opponent in >the fourth rank. You and Peter are counting different things: he is counting the >pawns in the fourth rank next to opponent pawns on their fifth rank (so for your >position that count is three, less than four). > It is not neccesary to distinguish which pawns can make an en-passant capture, >it is enough to know pawn can be taken en-passant. That is the reason Peter >counts the pawns on the fourth rank (which can be captured en-passant) and not >those which can make the capture. >José. Sorry! I mis-read your position. That happens to me when I do not set up the board and pieces (especially in the morning, here it is 11:00, too early for me!). José.
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