Author: Ricardo Gibert
Date: 16:18:30 05/30/99
Go up one level in this thread
actually, "M-bit key" would make my equation look silly. I didn't really say then what I meant to say. Oh well. Still you are not comparing the same thing. Your M is choosen to be prime to distribute the keys better. e.g. if M is even and most of the keys happen to be even, then only half the hash table gets used resulting in too many collisions.
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