Author: Robert Pope
Date: 13:32:55 06/16/99
It has been mentioned that the Swiss Pairing System is designed to find an absolute winner in a tournament, but if not enough rounds are played, the ordering of the lower places is not obvious. Is it also true then that the pairing system also does the opposite at the same time: finds the absolute worst-performing participant? I don't mean this question as an insult to any of the participants. I was just wondering if this is what the pairing system would do. Also, from my understanding, the pairings try to pair opponents with the same number of points. What if most or all of the participants with the same point score have already played each other? Can they be paired a second time?
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