Author: blass uri
Date: 12:29:44 08/09/99
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On August 09, 1999 at 13:46:37, José de Jesús García Ruvalcaba wrote: > I finally sat down and make all the computations from scratch and then >rechecked the results. >Number of 5+1 tablebases: 40 >Number of 4+2 tablebases: 200 >Number of 3+3 tablebases: 120 >Total number of six men tablebases: 360 > If there is interest I can explain how I got the results, they are simple >combinatorics problems. >José. Your calculation is wrong. For example the first number is 70 if I represent P=1,N=2,B=3,R=4,Q=5 then the I can represent every 5+1 material configuration(4+0 without kings) as 4 numbers and the number of possible configuration is 70 I can represent pppp configuration by 1111 pppn by 1112 pppb by 1113 You can count non decreasing sequence of 4 numbers(out of numbers 1,2,3,4,5) 1111 1112 1113 1114 1115 1222 1223 1224 1225 1233 1234 1235 1244 1245 1255 1333 1334 1335 1344 1345 1355 1444 1445 1455 1555 2222 2223 2224 2225 2233 2234 2235 2244 2245 2255 2333 2334 2335 2344 2345 2355 2444 2445 2455 2555 are only 45 options. You can translate every non decreasing sequence by adding 1 to the second number, adding 2 to the 3th number and adding 3 to the 4th number. The problem is how many increasing sequences you can choose from the numbers 1-8 and the answer is 8!/(4!*4!)=70 Uri
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