Author: Ralf Elvsén
Date: 01:37:58 09/13/99
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On September 12, 1999 at 20:46:26, Robert Hyatt wrote: >On September 12, 1999 at 19:51:14, Ralf Elvsén wrote: > >>I have read about some experiments where you let a >>program play against itself, but one version is searching >>one or more ply deeper than the other. From this >>you can estimate how much stronger a program gets >>given more time to search. >> >>Is it possible to perform an experiment like this on >>one computer according to the following? >> >>You take the principal variation given by the >>computer which looks like >> >>move1 move2 move3 ... >> >>i.e. the computer plays move1 and assumes the reply will be move2. >> >>Then you consistently make move2 (just like when you're cheating >>and look at the info from the computer) >>in reply to move1. Move2 is based on a search one ply >>more shallow than move1, so I figure this would work OK >>to simulate the abovementioned experiments. >> >>On the other hand, both moves "aim" for the same position >>(the one after the last move in the line). >> >>I haven't really been able to decide whether this would work or not. >>Presently I take the position that this would indeed give >>the same results as an ordinary experiment, but I sway back >>and forth, so if you think otherwise, >>you will not have a hard time to convince me :) >> >>Ralf > > >It won't quite work. Because (at least for me) I treat things at the root >differently than at ply > 1. For example, if I am in check at ply=1 I don't >extend because that would extend _every_ move and it makes no sense. But at >ply=2 it makes perfect sense to extend. This means that taking the first move >off the PV and assuming that the rest would be seen by a 1-ply shallower search >is not a good assumption... Ok, it won't work if you want to do a high quality experiment. But I guess that in general move2 is one ply "weaker" than move1? How much is a ply, a factor 3-4? That is about 100 rating points. The effect should be quite easy to see. Ralf
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