Author: Howard Exner
Date: 17:25:56 09/22/99
Go up one level in this thread
On September 22, 1999 at 13:42:26, Robert Hyatt wrote: >On September 22, 1999 at 13:40:37, Robert Hyatt wrote: > >>On September 22, 1999 at 11:46:29, Howard Exner wrote: >> >>>Do any of the programs with endgame tablebases solve this position? >>> >>>8/6Bp/6p1/2k1p3/4PPP1/1pb4P/8/2K5 b - - id Pos 111 - ECM98H.EPD; bm b3b2 >>> >>>It looks too difficult for non tablebase programs. >> >> >>Crafty solves it, but it takes longer than I would like to see... 11 minutes. >> >>here is the output: (quad xeon with all the 5 piece ending databases). >> >> 15-> 1:46 -0.09 1. ... Kd6 2. Bf8+ Ke6 3. f5+ Kf6 4. >> Kb1 Bd4 5. Ba3 h6 6. Bb2 h5 7. Bxd4 >> exd4 8. Kb2 hxg4 9. hxg4 d3 10. Kxb3 >> d2 11. Kc2 >> 16 2:21 -0.17 1. ... Kd6 2. Bf8+ Ke6 3. f5+ gxf5 >> 4. gxf5+ Kf6 5. Bc5 h5 6. Kb1 Kf7 7. >> Ba3 Kf6 8. Kc1 h4 9. Bb2 Be1 10. Kd1 >> Bf2 >> (3) 16-> 4:07 -0.17 1. ... Kd6 2. Bf8+ Ke6 3. f5+ gxf5 >> 4. gxf5+ Kf6 5. Bc5 h5 6. Kb1 Kf7 7. >> Ba3 Kf6 8. Kc1 h4 9. Bb2 Be1 10. Kd1 >> Bf2 >> (2) 17 6:09 -0.26 1. ... Kd6 2. Bf8+ Ke6 3. f5+ Kf6 4. >> Ba3 Bd4 5. Kb1 Bc3 6. g5+ Kf7 7. f6 >> Bd2 8. Bc1 <HT> >> 17 11:26 0.00 1. ... b2+ 2. Kc2 exf4 3. Bxc3 f3 4. >> Be1 Kd4 5. Bf2+ Kxe4 6. Ba7 Kf4 7. >> Bf2 Ke4 >> (4) 17-> 11:42 0.00 1. ... b2+ 2. Kc2 exf4 3. Bxc3 f3 4. >> Be1 Kd4 5. Bf2+ Kxe4 6. Ba7 Kf4 7. >> Bf2 Ke4 >> >>Don't know whether it will fail high at 18 or not, however... > > >depth 18 analysis: > > (3) 18 13:55 0.31 1. ... b2+ 2. Kc2 exf4 3. Bxc3 f3 4. > Be1 Kd4 5. Bf2+ Kxe4 6. Ba7 b1=Q+ 7. > Kxb1 Kd3 8. h4 Ke2 9. h5 gxh5 10. gxh5 > f2 11. Bxf2 Kxf2 12. Kc2 Ke3 I tried this on CM6000 and Rebel 10c but stopped after 30 minutes(this on an AMD 233). The 11 minutes looks impressive to me. In your final analysis on move number 9 rather than capturing with gxh5 the winning move is g5, so that the black king can capture both of white's pawns. However in an actual game Crafty would no doubt see that when it reached that point in the game. My guess is that we won't see to many people posting that program X finds this one. Hope I'm wrong in this guess. Now I'm also wondering if tablebases will help here as after the initial exchanges there remain two pawns each on the king's side?
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