Author: Bruce Moreland
Date: 16:36:56 10/20/99
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On October 20, 1999 at 19:11:30, Paul Svelmoe wrote: >Hi, > Last month, someone wrote... >>The number of positions should be 462, so evaluated: >> >> 1 x 4 = 1 x 33 = 33 white king in a1 >> 3 x 6 = 3 x 58 = 174 white king in b1, c1, d1 >> 3 x 9 = 3 x 55 = 165 white king in c2, d2, d3 >> 3 x 9 = 3 x 30 = 90 white king in b2, c3, d4 >> ---------- >>Total 462 > >Is it true? Could someone explain this to me? Already after the 1st line that >says ... >> 1 x 4 = 1 x 33 = 33 white king in a1 >...I am confused. If the white K is on a1, then the black king can be anywhere >except a1, b1, a2, and b2, therefore there are 60 legal positions for W Ka1, not >33. Thanks! >Paul Symmetry is being taken into account. WKa1 BKc1 is the same as WKa1 BKa3. If you confine the black king to the a1..h1..h8 triangle, there are 33 legal places to put it. If you don't take into account symmetry, there are 3612 legal placements of two kings. bruce
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