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Subject: Re: help with position

Author: Will Singleton

Date: 13:26:57 11/11/99

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On November 10, 1999 at 23:16:48, Bruce Moreland wrote:

>On November 10, 1999 at 20:32:58, Will Singleton wrote:
>
>>r2r2k1/pp3ppp/2n2b2/4p3/2N5/1PP2B2/1P3PPP/R2R2K1 b - -
>>
>>This position gives my program fits.  Some stronger progs solve it easily.  It
>>appears to be a simple case of extending on captures, and then doing the qsearch
>>right, which I apparently am not.
>>
>>Here's the main line which should be found:
>>Rxd1 Rxd1 Rd8 Rxd8 Nxd8 Nd6 b6 Nc8 Bg5 Nxa7 Bc1 and gets the pawn back.
>>
>>It appears that you need 13 ply to see that the bishop can get the pawn back.
>>Extending on a capture that brings material back to nominal, there are 2
>>extensions in the above main line, so you now need 11 ply.  The qsearch reduces
>>this to 10.  And that's what my program needs, 10 ply.  Seems too long.
>>
>>I would love to find this sooner without blowing up the tree.
>>
>>(from a game on ICC today, Postmodernist vs Amateur)
>
>How do you do on Bratko Kopec #22?
>
>2r2rk1/1bqnbpp1/1p1ppn1p/pP6/N1P1P3/P2B1N1P/1B2QPP1/R2R2K1 b - - 0 1
>
>The key is Bxe4.  If you have recapture problems it may take a while to find,
>especially on a slow machine.
>
>bruce

BK 22 seems ok.

  2     -34     0.02      1338    40140
  3      -2     0.08      2911    21780  Nh7 Bd4 Bf6
  4     -12     0.22      8769    23880  Nh7 Bd4 Bf6 Nc3
  5     -16     1.14     37714    30540  Re8 Bd4 e5 Bc3 Nc5 Nxc5 Qxc5
  6      56     4.22    145350    33240  Bxe4 Bxe4 Qxc4 Qxc4 Rxc4 Nxb6 Rxe4 Nxd7

Will




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