Author: José de Jesús García Ruvalcaba
Date: 10:34:21 11/30/99
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On November 30, 1999 at 12:51:48, Dann Corbit wrote: >On November 30, 1999 at 12:19:45, Dave Gomboc wrote: >[snip] >>Round-Robin -> Swiss just doesn't make sense. If you have already had everyone >>play each other once (or twice, if it's a double round-robin), why would you >>then have a swiss for the top spots? Your tournament is already over. > >You don't have all the players participate, just the top players. > >Suppose you have 12 entries in a contest. They play 24 games (12 each >white/black) using a round-robin format. This will determine an approximate ELO >for the pool. Then, for the top 4 players, have a swiss tournament of several >rounds. > Hi Dann, what you say does not make any sense. You can not have a four-player swiss tournament of several rounds. The simple reason is that in a swiss tournament you can not face the same opponent twice. With four players, that makes for three rounds at most, and in that case you have actually played a non-standard round robin. >The goal I would like to reach is a fair tournament. In such a tournament, the >best program has a good chance of winning. The separation between top programs >is very small. In order to find out which one is really the best, careful >design of the tournament is needed. Two or three rounds of a swiss tournament >with programs of unknown strength is little more than a crap-shoot. > But two or three rounds more than log(number of players), rounded up to the next integer, is not. Even if the strongest entry is upsetted in the first round, if it is really stronger it has a chance to win the tournament. >On the other hand, the programmers are reluctant to play a lot of games. So >perhaps having a 3rd or 4th place program win does not really matter. It's >still a neat title to hang on the wall and it gives the underdogs a fighting >chance to win.
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