Author: Marek Soszynski
Date: 06:08:19 01/22/00
There have been one or two questions about how FritzMarks are calculated. Well, for the Short test type the following position is used: Hamilton-Haygarth, 1956 [D] 1r5r/3b1pk1/3p1np1/p1qPp3/p1N1PbP1/2P2PN1/1PB1Q1K1/R3R3 b - - 0 1 But note that Fritz isn't interested in the solution, which is ...Nxg4 and would take minutes to get, but rather in how many nodes/sec are achieved by the Fritz 5.32 engine on the particular PC in question. _______________ Marek Soszynski Sutton Coldfield Chess Club http://www.brum2000.swinternet.co.uk/
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