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Subject: Re: correction

Author: Jari Huikari

Date: 06:53:12 02/17/00

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Number of different games would then be
>(20*20)**5 + (30*30)**35, which is about 2E116.
>(2000000000000000000000000000000000000000000000000000000000000
> 00000000000000000000000000000000000000000000000000000000)

Sorry, of course (20*20)**5 * (30*30)**35
                            =

and more accuratale it's 2.56323E116

					Jari



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