Author: Rafael Andrist
Date: 10:34:56 01/24/01
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On January 24, 2001 at 09:07:30, leonid wrote: >Hi! > >If you like to solve some easy force mate, here is one. > >[D]2r4k/3b1p2/b2b1N2/bPrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - - > sorry, but if the position is displayed correctly on my screen, it is illegal! there are 5 black knights, 7 black bishops and 1 black pawn. To get 5 black knights and 7 black bishops, 8 pawn promotions are needed, so there can't be 1 black pawn on the board. Can you please correct the misstake (typing error?)? Thanks Rafael B. Andrist
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