Author: Uri Blass
Date: 11:52:33 01/24/01
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On January 24, 2001 at 13:34:56, Rafael Andrist wrote: >On January 24, 2001 at 09:07:30, leonid wrote: > >>Hi! >> >>If you like to solve some easy force mate, here is one. >> >>[D]2r4k/3b1p2/b2b1N2/bPrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - - >> > >sorry, but if the position is displayed correctly on my screen, it is illegal! >there are 5 black knights, 7 black bishops and 1 black pawn. To get 5 black >knights and 7 black bishops, 8 pawn promotions are needed, so there can't be 1 >black pawn on the board. Can you please correct the misstake (typing error?)? >Thanks You are right. It is too easy to prove mate in an illegal position. Here is the right position I do not know how many moves black need to mate but it seems that not many because Junior5.9 has no problem to see more than 20 pawns advantage for black. [D]2r4k/3b4/b4N2/1PrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - - 0 1 Are you satisfied? Uri
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