Author: Uri Blass
Date: 04:00:52 05/18/01
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On May 18, 2001 at 02:29:46, Dann Corbit wrote: >On May 18, 2001 at 01:26:51, Uri Blass wrote: >[snip] >>I agree with the idea except that 168 is too much and you should use 155 bit >>numbers. >> >>My counting program proved that the number of legal positions is less than 2^155 > >Do you actually have a 155 bit encoding for chess positions? > >If so, I would be keenly interested to see it. >[snip] I have the following problems in doing it. 1)I cannot use big integers and when I try to create a default project for my modified program that I got from you more than a year ago I get the following error fatal error C1083: Cannot open include file: 'qhead.h': No such file or directory Error executing cl.exe. Here is the relevant program that you sent me(I believe that I did not modify it but I may be wrong and maybe i modified it when i tried to fix the problem without success) #include <iostream.h> #include "qhead.h" #include "qfloat.h" int main (void) { char x1, x2, x3, x4, x5, y1, y2, y3, y4, y5, j, i, a; qfloat k, n = 0; qfloat m[65], w[65]; m[0] = 1; w[0] = 0; for (i = 1; i < 65; i++) { w[i] = 0; m[i] = m[i - 1] * (qfloat)(double) i; } n = 0; for (x1 = 0; x1 < 9; x1++) { cout << "new x1:" << x1 << endl; for (x2 = 0; x2 < 11 - x1; x2++) { cout << "new x2:" << x2 << endl; for (x3 = 0; (x3 < 11 - x1 && x1 + x2 + x3 < 13); x3++) for (x4 = 0; (x4 < 11 - x1 && x1 + x2 + x4 < 13 && x1 + x3 + x4 < 13 && x1 + x2 + x3 + x4 < 15); x4++) for (x5 = 0; (x5 < 10 - x1 && x1 + x2 + x5 < 12 && x1 + x3 + x5 < 12 && x1 + x4 + x5 < 12 && x1 + x2 + x3 + x5 < 14 && x1 + x2 + x4 + x5 < 14 && x1 + x3 + x4 + x5 < 14 && x1 + x2 + x3 + x4 + x5 < 16); x5++) { k = m[x2] * m[x3] * m[x4] * m[x5]; i = 0; if (x2 > 2) i = i + x2 - 2; if (x3 > 2) i = i + x3 - 2; if (x4 > 2) i = i + x4 - 2; if (x5 > 1) i = i + x5 - 1; for (y1 = 0; y1 < 9; y1++) for (y2 = 0; y2 < 11 - y1; y2++) for (y3 = 0; (y3 < 11 - y1 && y1 + y2 + y3 < 13); y3++) for (y4 = 0; (y4 < 11 - y1 && y1 + y2 + y4 < 13 && y1 + y3 + y4 < 13 && y1 + y2 + y3 + y4 < 15); y4++) for (y5 = 0; (y5 < 10 - y1 && y1 + y2 + y5 < 12 && y1 + y3 + y5 < 12 && y1 + y4 + y5 < 12 && y1 + y2 + y3 + y5 < 14 && y1 + y2 + y4 + y5 < 14 && y1 + y3 + y4 + y5 < 14 && y1 + y2 + y3 + y4 + y5 < 16); y5++) { j = 0; if (y2 > 2) j = j + y2 - 2; if (y3 > 2) j = j + y3 - 2; if (y4 > 2) j = j + y4 - 2; if (y5 > 1) j = j + y5 - 1; a = x1 + x2 + x3 + x4 + x5 + y1 + y2 + y3 + y4 + y5; if ((i <= 2 * (15 - y1 - y2 - y3 - y4 - y5) + (15 - x1 - x2 - x3 - x4 - x5)) && (j <= 2 * (15 - x1 - x2 - x3 - x4 - x5) + (15 - y1 - y2 - y3 - y4 - y5))) w[a] = w[a] + (m[48] / (m[x1] * m[y1] * m[48 - x1 - y1])) * (m[64 - x1 - y1] / (k * m[y2] * m[y3] * m[y4] * m[y5] * m[62 - x1 - y1 - x2 - x3 - x4 - x5 - y2 - y3 - y4 - y5])); } } } } k = 0; for (i = 0; i < 31; i++) { cout << i << w[i] << endl; k += w[i]; } cout << k << endl; return 0; } The best that I know to do with visual c++ is __int64 and it is not enough. 2)I do not know an easy way to translate a material structure to a number. If you can give me a code to translate every pseudo legal position of 32 pieces to a number then it can help. By the words pseudo legal position with 32 pieces I mean position when all the pieces are at different squares when all the pawns are not in the first rank or the last rank. By translating to numbers I mean to the following assumptions: a)Every position gets a different number b)there is a position that is translated to 0 c)if there is a position that is translated to n when n is not 0 then there is a position that is translated to n-1. Uri
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