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Subject: Re: A question about a specific 8 man tablebase (correction)

Author: Tony Werten

Date: 10:03:55 11/13/01

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On November 13, 2001 at 10:19:46, Robert Hyatt wrote:

>On November 13, 2001 at 05:16:10, Tony Werten wrote:
>
>>On November 13, 2001 at 03:22:13, derrick gatewood wrote:
>>
>>>How much time and space would it take to compile the tablebase for an endgame
>>>where each side had 3 pawns?  would this be possible or it simple to large?  It
>>>seems like it would be so large since pawns dont have much movement.  Has this
>>>already been performed so I dont have to waste my time?  The "Little Game" as it
>>>is called on chess.net is my nemesis and I really want to figure out this game
>>>and that tablebase would be all I would need to study it in depth.  Thank you..
>>>as far as time goes,  my system is 1.575 ghz athlon,  with 512 megs of PC2100
>>>ram
>>
>>Simple math suggests that the table should have 443,247,013,440 entries
>>(excluding ep-rights). With 1 byte per position, your memory seems to be less
>>than a factor 1000 off.
>>
>>Tony
>
>
>It is worse than that.  The file will have roughly 2^48 _entries_ 8 pieces
>with 64 squares each. that is 262 terrabytes.  Actually 262 trillion entries
>of probably at least two bytes each, so 512 terrabytes roughly.

6 pawns have less positions than 64, the 3 pawns each cannot have different
order (pawn on a2,b2=b2,a2), kings have 1806.

So total number is 1806*(48!/(45!*3!))*(45!/(3!*42!))=443247013440

Of course the problem of not having subsets stays.

Tony


>
>Pretty big.  :)



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