Author: KarinsDad
Date: 05:52:01 12/24/03
Go up one level in this thread
On December 24, 2003 at 03:14:14, Russell Reagan wrote: >This portion below can be encoded using no more than 88-bits, assuming no >captures or promotions (even with some odd promotions I tried, it still equals >88-bits, since there must be a capture in order for there to be a promotion). >That would give us a total of 166 bits. Somehow Reinhard is able to do this in >81-bits. If that is correct, then we should be able to represent the position in >159 bits. > Yup. Actually, there can be 3 promotions for every pawn capture. And in fact, it can be consistently encoded using less than 88 bits, but 81? I can't wait to see that. ;) In the meantime, Happy Holidays, I'm off to the airport and vacation. KD
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