Author: Peter Berger
Date: 14:18:55 06/09/04
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On June 09, 2004 at 13:24:54, José de Jesús García Ruvalcaba wrote: >On June 09, 2004 at 08:31:21, Peter Berger wrote: > >> >>I enjoyed reading your posts but you generalized the problem too much IMHO. I >>specifically referred to legal Swiss pairings only. I agree that there will >>always be some way of pairing left but not one that also follows the much >>stricter rules for Swiss pairings. >> >>If you have sufficient time you can look them up here: >>http://www.fide.com/official/handbook.asp?level=C04 >> >>Peter > >Well, I did not generalise the problem too much. The FIDE swiss system rules are >for sure strict, but they allow score brackets to be melted together if there is >no other way of producing a pairing. Doing that succesvely until we get only one >bracket (with n-3 rounds for n players that could easily happen according to the >rules), we are in the situation I described. > >See >http://www.fide.com/official/handbook.asp?level=C0401B >B.3 is a relative pairing criterium. > >in C.13 of >http://www.fide.com/official/handbook.asp?level=C0401C >it is shown under which circumstances the last two score brackets are joined. > >And in 9.6 of >http://www.fide.com/official/handbook.asp?level=C0402B >it is described how and in which direction the median score group is extended. > >If you read carefully, in those pages the swiss system is described twice, and >both descriptions are not equivalent. In one of them the score brackets are >paired from up to bottom, in that case the C.13 rule is relevant. In the other >one the brackets above the median group are paired from up to bottom, then the >brackets below the median group are paired from bottom to up, and at the end the >median group is paired, then is the 9.6 rule relevant. >Anyway, as long as there is a pairing which does not break the absolute pairing >criteria, there is a legal pairing. As I said, it can be guaranteed up to n-3 >rounds. >José. You sound pretty convincing José :) - I stand corrected I guess. Only thing that might possibly create additional problems for the mathematical proof are the colour rules, especially the absolute ones. Three times the same colour for a participant is never allowed without exceptions - a problem? Greetings to Goettingen, Peter
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