Author: Ed Schröder
Date: 00:07:42 01/26/00
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On January 25, 2000 at 23:57:33, Ernst A. Heinz wrote: >> In a one by one setting it does not matter at all. > >Still not convinced: a quiescence node that produces a direct >"stand pat" cutoff obviously generates less work than one >which fails to do so -- even in hardware! *** QED *** > >Or am I missing something? > >=Ernst= Something else... I always wondered about this free 4-ply evaluation. I can understand that evaluation for the current position done in hardware is possible in a few cycles. I can't understand this also to be true for 4 plies as it should involve: search, hash table, q-search etc. In other words a complete chess program. Ed
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