Author: Robert Hyatt
Date: 20:07:17 03/09/00
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On March 09, 2000 at 21:58:18, Tom Kerrigan wrote: >On March 09, 2000 at 21:03:17, Robert Hyatt wrote: > >>On March 09, 2000 at 17:34:47, Tom Kerrigan wrote: >> >>>On March 09, 2000 at 16:35:50, Pierre Bourget wrote: >>> >>>>>Never heard of an H7 or H8 processor. But many older chess programs were based >>>>>on Motorola 68000 series. 68000 is 16 bit, and 68020 is 32 bit. You can't just >>> >>>I believe the 68000 is 32-bit. It has a 24-bit address bus to reduce the >>>pincount. >>> >> >>He is right. the 6800 was 8 bit, the 68000 was 16 bit. the 020 was the >>first 32 bit member of the family... > >It depends on how you count bits. 16 bit data bus, 24 bit addresses, but any >comp org textbook will tell you that the 68000 has 8 32-bit general purpose data >registers and 8 32-bit address registers, and most of the instructions operated >on 32 bits at a time. > >If you really want to say a processor is n-bit when it has an n-bit data bus, be >my guest. But then most PCs become 64-bit, which I don't think you agree with. > >-Tom that's the wrong way to measure this. the 8080 was a 16 bit cpu if you use that logic. The 68000 had a 16 bit bus. I taught hardware design courses at USM many years ago... Motorola donated what they called "notebook computers" back then... a motherboard and cpu with external interface logic, and it all fit into a loose-leaf ring binder. :) but the cpu was 16 bit by any measure I would name... otherwise what do we call the 80286? Maybe the 68000 could be thought of as a hybrid, but I always look at the bus width as the first test of a 32 bit machine... it has to be at least 32 bits wide... that 68000 (that I had anyway) didn't support that... the next one I used was an 030 in an early sun workstation.
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