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Subject: Re: If you like to solve illegal mate...

Author: Uri Blass

Date: 11:52:33 01/24/01

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On January 24, 2001 at 13:34:56, Rafael Andrist wrote:

>On January 24, 2001 at 09:07:30, leonid wrote:
>
>>Hi!
>>
>>If you like to solve some easy force mate, here is one.
>>
>>[D]2r4k/3b1p2/b2b1N2/bPrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - -
>>
>
>sorry, but if the position is displayed correctly on my screen, it is illegal!
>there are 5 black knights, 7 black bishops and 1 black pawn. To get 5 black
>knights and 7 black bishops, 8 pawn promotions are needed, so there can't be 1
>black pawn on the board. Can you please correct the misstake (typing error?)?
>Thanks

You are right.
It is too easy to prove mate in an illegal position.

Here is the right position

I do not know how many moves black need to mate but it seems that not many
because Junior5.9 has no problem to see more than 20 pawns advantage for black.

[D]2r4k/3b4/b4N2/1PrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - - 0 1

Are you satisfied?

Uri



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