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Subject: Re: If you like to solve illegal mate...

Author: Uri Blass

Date: 11:52:33 01/24/01

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On January 24, 2001 at 13:34:56, Rafael Andrist wrote:

>On January 24, 2001 at 09:07:30, leonid wrote:
>>If you like to solve some easy force mate, here is one.
>>[D]2r4k/3b1p2/b2b1N2/bPrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - -
>sorry, but if the position is displayed correctly on my screen, it is illegal!
>there are 5 black knights, 7 black bishops and 1 black pawn. To get 5 black
>knights and 7 black bishops, 8 pawn promotions are needed, so there can't be 1
>black pawn on the board. Can you please correct the misstake (typing error?)?

You are right.
It is too easy to prove mate in an illegal position.

Here is the right position

I do not know how many moves black need to mate but it seems that not many
because Junior5.9 has no problem to see more than 20 pawns advantage for black.

[D]2r4k/3b4/b4N2/1PrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - - 0 1

Are you satisfied?


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