Author: Uri Blass
Date: 13:58:04 01/24/01
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On January 24, 2001 at 14:52:33, Uri Blass wrote: >On January 24, 2001 at 13:34:56, Rafael Andrist wrote: > >>On January 24, 2001 at 09:07:30, leonid wrote: >> >>>Hi! >>> >>>If you like to solve some easy force mate, here is one. >>> >>>[D]2r4k/3b1p2/b2b1N2/bPrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - - >>> >> >>sorry, but if the position is displayed correctly on my screen, it is illegal! >>there are 5 black knights, 7 black bishops and 1 black pawn. To get 5 black >>knights and 7 black bishops, 8 pawn promotions are needed, so there can't be 1 >>black pawn on the board. Can you please correct the misstake (typing error?)? >>Thanks > >You are right. >It is too easy to prove mate in an illegal position. > >Here is the right position > >I do not know how many moves black need to mate but it seems that not many >because Junior5.9 has no problem to see more than 20 pawns advantage for black. > >[D]2r4k/3b4/b4N2/1PrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - - 0 1 > >Are you satisfied? > >Uri I can add that Junior5.9 says that it is mate in at most 12 moves pv:1...Bdxb5 2.Nxe4 Bxe2+ 3.Qxe2 Bxe4 4.Rxg4 Bxe2+ 5.Kf2 Bxg4 6.Rxg4 Rc2+ 7.Kf1 Bd3+ 8.Re2 Bxe2+ 9.Kg1 Ndf3+ 10.Kh1 Rc1+ 11.Bxc1 Rxc1+ 12.Rg1 Rxg1# Uri
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