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Subject: Re: If you like to solve illegal mate...

Author: Uri Blass

Date: 13:58:04 01/24/01

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On January 24, 2001 at 14:52:33, Uri Blass wrote:

>On January 24, 2001 at 13:34:56, Rafael Andrist wrote:
>>On January 24, 2001 at 09:07:30, leonid wrote:
>>>If you like to solve some easy force mate, here is one.
>>>[D]2r4k/3b1p2/b2b1N2/bPrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - -
>>sorry, but if the position is displayed correctly on my screen, it is illegal!
>>there are 5 black knights, 7 black bishops and 1 black pawn. To get 5 black
>>knights and 7 black bishops, 8 pawn promotions are needed, so there can't be 1
>>black pawn on the board. Can you please correct the misstake (typing error?)?
>You are right.
>It is too easy to prove mate in an illegal position.
>Here is the right position
>I do not know how many moves black need to mate but it seems that not many
>because Junior5.9 has no problem to see more than 20 pawns advantage for black.
>[D]2r4k/3b4/b4N2/1PrNnbb1/3nb1nn/Pn5P/1B2RQR1/4RKR1 b - - 0 1
>Are you satisfied?

I can add that Junior5.9 says that it is mate in at most 12 moves

pv:1...Bdxb5 2.Nxe4 Bxe2+ 3.Qxe2 Bxe4 4.Rxg4 Bxe2+ 5.Kf2 Bxg4 6.Rxg4 Rc2+
7.Kf1 Bd3+ 8.Re2 Bxe2+ 9.Kg1 Ndf3+ 10.Kh1 Rc1+ 11.Bxc1 Rxc1+ 12.Rg1 Rxg1#


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