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Subject: Re: I'm wrong about 10-0 vs 60-40

Author: Walter Koroljow

Date: 14:16:00 02/04/01

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On February 04, 2001 at 13:28:03, Uri Blass wrote:

>On February 04, 2001 at 12:48:36, Walter Koroljow wrote:
>
>>On February 03, 2001 at 18:58:36, Uri Blass wrote:
>>
>><snip>
>>
>>>Assume level of confidence 97% in all of your tests.
>>>
>>>If you reject H0 in 3% of the times then it is possible that you are always
>>>wrong when you reject H0(for example when always We=0.5).
>>>
>>>If you reject H0 in 50% of the times then you are wrong only in at most 6% of
>>>the cases that you reject H0(to be more exact I need to say if the probability
>>>to reject H0 is 50% but the probability is something that you do not know and
>>>the % of the cases that you rejected H0 practically is something that you know).
>>>
>>>Uri
>>
>>If I interpret you correctly, I disagree.  Let us work at the 97% confidence
>>level with H0 as before.
>>
>>We agree that the highest Type I error rate (false rejection of H0) occurs if,
>>for each test we run, we have We = 0.5.  In fact the error rate will be exactly
>>3% then.  If We = 0.8, the error rate will be less -- assume 1% for convenience.
>> Let me make my case by example.
>>
>>Suppose that in the population that we test repeatedly we have:
>>
>>34% We = 0.5 (H0 true)
>>33% We = 0.8 (H0 true)
>>33% We = 0.2 (H0 false).
>>
>>Then the Type I error rate for the case H0 true is (.34*3% +.33*1%)/(.34+.33) =
>>2.01%
>>This is less than 3%.  I cannot see how the error rate could ever exceed 3% for
>>any mix of We.
>>
>>For the case We = 0.2, a Type I error is impossible since H0 is false.  So the
>>overall Type I error rate
>>will be:
>>
>>(.34*3% + .33*1% + .33*0%)/(.34+.33+.33) = 1.35%, of course also less than 3%.
>
>Basically I guess that we agree and there is some misunderstanding in the
>language
>
>I will try to explain it more clearly only by math.
>
>From my post:
>"If you reject H0 in 3% of the times then it is possible that you are always
>wrong when you reject H0(for example when always We=0.5)."
>
>Explanation:
>
>If P(You reject H0)=0.03 then it is possible that
>p(you are wrong| you reject H0)=1.
>
>
>From my post:
>"If you reject H0 in 50% of the times then you are wrong only in at most 6% of
>the cases that you reject H0(to be more exact I need to say if the probability
>to reject H0 is 50% but the probability is something that you do not know and
>the % of the cases that you rejected H0 practically is something that you
>know)".
>
>Explanation:
>
>If p(You reject H0)=0.5 then
>p(you are wrong| you reject H0)<=0.06
>
>Uri

O.K., I agree.  Maybe we should just talk mathematics.  Spoken language is very
vague.




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