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Subject: Re: Is the Depth directly proportional to the program's strength? (YES!)

Author: Tony Werten

Date: 04:33:50 02/07/02

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On February 07, 2002 at 06:29:47, Sune Fischer wrote:

>On February 07, 2002 at 04:55:23, Tony Werten wrote:
>
>>On February 06, 2002 at 10:45:25, Sune Fischer wrote:
>>
>>>On February 06, 2002 at 10:30:15, Tony Werten wrote:
>>>>>So it would seem, but the search is exponential and not linear.
>>>>>I think you should not consider the "depth" but rather the number of nodes
>>>>>searched.
>>>>
>>>>Doesn't make a difference. Depth and number of nodes are the "same".
>>>
>>>Not at all, nodes is an exponential function of depth.
>>
>>Yes, should have said highly related.
>
>I had a feeling that "same" was a bit fuzzy ;)
>
>>My point is that when you give a program 1M nodes more than the other, at low
>>depths this might be a couple of ply, at higher depths, it's less than a ply.
>>
>>Calling this diminishing returns isn't correct IMO. It's just the way a
>>searchtree works.
>
>Yes, and we wouldn't be doing that, we would be multiplying by a BF factor, e.g.
>doubling the search time each time.
>The question is, if we double up every time, do we see diminishing returns at
>some point, or will there be a constant change in rating with each doubling?
>
>If you compare computers rating with humans, you will see that almost all
>programs are a few hundred elo higher in blitz and bullet than in standard
>tournament time control.
>Of cause we don't know what kind of diminishing returns a human has, so it
>doesn't tell all that much, but there is a clear tendency.
>
>
>>I believe DR is the fact that 4-3 scores a bit better then 8-6
>>and 12-9
>
>That would mean diminishing returns.

That's what the DR stands for :)

I believe there is DR but not as big as the ply vs ply+1 tests indicate. Even
more if there was no DR (ie 12-9 scores same as or better than 4-3), ply vs
ply+1 would still indicate there was.

Tony

>
>>OK. Hmm, how about giving a limited amount of petrol to accelerate a car ? If
>>the first car goes slow, you can go twice as fast and arrive a few hours befor
>>him. Else it might only be a few percent and a few minutes.
>
>What you are thinking of is the function 1/x (because time=distance/velocity),
>it shows similar characteristics as exp(-x), but is not the same.
>
>-S.



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