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Subject: Re: Evaluation in Rebel

Author: Russell Reagan

Date: 11:57:22 01/07/03

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+------+------+------+------+------+------+------+------+
| BIT0 | BIT1 | BIT2 | BIT3 | BIT4 | BIT5 | BIT6 | BIT7 |
+------+------+------+------+------+------+------+------+
|      Number of     | PAWN |KNIGHT| ROOK | QUEEN| KING |
|      ATTACKERS     |      |BISHOP|      |      |      |
+------+------+------+------+------+------+------+------+

Ed,

On your webpage you have the above diagram. I am curious what you use bits 3-7
for. The reason I ask is because what if there are two queens and one knight
attacking a square? Then the table will look like this:

+------+------+------+------+------+------+------+------+
| BIT0 | BIT1 | BIT2 | BIT3 | BIT4 | BIT5 | BIT6 | BIT7 |
+------+------+------+------+------+------+------+------+
|      Number of     | PAWN |KNIGHT| ROOK | QUEEN| KING |
|      ATTACKERS     |      |BISHOP|      |      |      |
+------+------+------+------+------+------+------+------+
|  1   |   1  |  0   |  0   |  1   |  0   |  1   |  0   |
+------+------+------+------+------+------+------+------+

How do you know if there are two queens and one knight/bishop attacking, or two
knights/bishops and one queen?

Let's look at an example:

[D]4kq2/2bq2b1/8/4p3/4P3/2Q2N2/1Q2K1B1/8 w - - 0 1

In this position, the attack board for white[e5] is going to be:
+------+------+------+------+------+------+------+------+
| BIT0 | BIT1 | BIT2 | BIT3 | BIT4 | BIT5 | BIT6 | BIT7 |
+------+------+------+------+------+------+------+------+
|      Number of     | PAWN |KNIGHT| ROOK | QUEEN| KING |
|      ATTACKERS     |      |BISHOP|      |      |      |
+------+------+------+------+------+------+------+------+
|  1   |   1  |  0   |  0   |  1   |  0   |  1   |  0   |
+------+------+------+------+------+------+------+------+

In this other position:
[D]4kq2/2bq2b1/8/4p3/4P3/2B2N2/1Q2K1Q1/8 w - - 0 1
The attack board for white[e5] is exactly the same as in the previous position,
but in this case, white can win the pawn, but in the first position white can
not win the pawn.

When two attack boards are the same, as in these two positions, how do you
determine that the latter position is a gain of 1 pawn and the first position is
not?

I understand how you compute the attack table, but I am a little confused about
how you use this information to arrive at a conclusion, like "white wins 1
pawn".

Thanks,
Russell



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