Author: Tony Werten
Date: 07:25:43 02/23/03
Go up one level in this thread
On February 23, 2003 at 09:59:34, Mike Byrne wrote: >On February 23, 2003 at 07:17:50, Tony Werten wrote: > >>On February 22, 2003 at 16:58:12, Robert Hyatt wrote: >> >>>On February 22, 2003 at 09:29:47, Rolf Tueschen wrote: >>> >>>>On February 22, 2003 at 09:25:16, Robert Hyatt wrote: >>>> >>>>>On February 22, 2003 at 08:54:30, Rolf Tueschen wrote: >>>>> >>>>>>I read 6: Ikarus 3.5 / 6 2b= 13w+ 1w= 4b= 3w- 14b+. >>>>>> >>>>>>So that means that Ikarus although playing the placed 1, 2, 3, 4 progs, it could >>>>>>get full points against the last and pre-last. Placed om 14 and 13. >>>>>>Is this ok? Something seems to be wrong or biased. Point is that a game against >>>>>>14 is a SURE win. That is as if a top program after a loss or two draws got a >>>>>>point for free. Note Ikarus had 2,5 pts before playing Matador with 0.5 pts. >>>>>> >>>>>>Could some expert explain why such things are still possible? >>>>>> >>>>>>Rolf Tueschen >>>>> >>>>> >>>>>Too few programs, too many rounds. >>>> >>>>Also, many progs get a "good" result and that is also a good side-effect we >>>>should consider. What would be the optimal number of rounds for 14 participants? >>>> >>>>Rolf Tueschen >>> >>>optimal number of rounds is log2(N) rounded up to the next integer value. >>>In this case 4 rounds, is optimal, 5 acceptable. >> >>That might be true in general, but depends on the participants. When 8 programs >>are very equal in strength, you want at least 7 rounds to make sure that there >>is at least a little chance they have played each other. >> >>Tony > > >You just described a round robin which is totally different - if you have 8 >programs and 7 rounds, you play a round robim and every player will play each >other once. The formula is for use in a swiss tournament. No, I was talking about 14 programs, with 8 being more or less equal. Tony
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