Author: Robert Allgeuer
Date: 06:10:37 11/21/03
Go up one level in this thread
On November 20, 2003 at 22:44:28, Dann Corbit wrote: >On November 20, 2003 at 22:41:09, Dann Corbit wrote: > >>On November 20, 2003 at 22:27:14, Dann Corbit wrote: >> >>>On November 20, 2003 at 22:21:46, Dann Corbit wrote: >>> >>>>On November 20, 2003 at 19:50:12, Uri Blass wrote: >>>> >>>>>On November 20, 2003 at 18:57:24, J. C. Boco wrote: >>>>> >>>>>>Doubling the processor speed or the time for thinking adds about 80 points to >>>>>>the SSDF-computer-ratings. But PC's are already running so fast that doubling >>>>>>their speed might mean searching at 15ply instead of 14ply. >>>>> >>>>>How do you get it? >>>>> >>>>>Based on the ssdf list even being 3 times faster does not give 80 elo. >>>>>A1200 is often more than 3 times faster than K6-450 >>>>> >>>>>Uri >>>> >>>>This query: >>>>SELECT a.engine, (a.Elo - b.Elo)/(1200.0/450.0) AS EloDiff >>>>FROM Ssdf AS a, Ssdf AS b >>>>WHERE a.Engine = b.Engine >>>> >>>>And >>>> a.Hardware like "*1200 MHz*" >>>> >>>>And >>>> b.Hardware like "*450 Mhz*" >>>> >>>>Order by (a.Elo - b.Elo)/(1200.0/450.0) Desc >>>> >>>>Returns this result set: >>>> >>>>engine EloDiff >>>>Gandalf 4.32h 50.625 >>>>Crafty 18.12/CB 50.25 >>>>Gandalf 5.0 42 >>>>Fritz 7.0 42 >>>>Deep Fritz 7.0 41.25 >>>>Rebel Century 4.0 40.125 >>>>Hiarcs 8.0 36.75 >>>>Chess Tiger 14.0 CB 32.25 >>>>Gambit Tiger 2.0 27.375 >>>>Deep Fritz 25.125 >>>>Junior 7.0 22.875 >>>>Chess Tiger 15.0 20.625 >>>>Shredder 5.32 20.25 >>>> I do believe that the formula should be (a.Elo - b.Elo)/ld(1200.0/450) instead of (a.Elo - b.Elo)/(1200.0/450.0) with ld being the log to the base 2. With this dataset this would give roughly a median (i.e. Hiarcs) of 69 ELO points gain for doubling processor speed, minimum of 38 for Shredder 5.32, max 95 for Gandalf (under the condition that processor speed really scales linearly with the clock rate). Robert
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