Author: Dann Corbit
Date: 19:06:40 06/11/04
Go up one level in this thread
On June 11, 2004 at 20:51:35, Uri Blass wrote:
>On June 11, 2004 at 20:39:33, Joshua Shriver wrote:
>
>>
>>Parse your argv data.
>>
>>Believe argv[0] is the filename of the executable being run.
>>
>>int main(int argc, char *argv[])
>>{
>>
>> printf("%s\n", argv[0]);
>>
>> return 0;
>>}
>
>Based on Dann Corbit's post I cannot trust it so I think that I will not try to
>use it inspite of the fact that now it works because tomorrow with a new
>compiler it may stop to work.
>
>Here are Dann Corbit's words:
>
>This information from the C-FAQ may be relevant:
>19.31: How can my program discover the complete pathname to the
> executable from which it was invoked?
>
>A: argv[0] may contain all or part of the pathname, or it may
> contain nothing. You may be able to duplicate the command
> language interpreter's search path logic to locate the
> executable if the name in argv[0] is present but incomplete.
> However, there is no guaranteed solution.
>
>Uri
Uri is correct. A better version of the test program would look like this:
int main(int argc, char *argv[])
{
if (argc > 0)
printf("%s\n", argv[0]);
else
puts("program name unknown");
return 0;
}
This page took 0 seconds to execute
Last modified: Thu, 15 Apr 21 08:11:13 -0700
Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.