Author: Richard Pijl
Date: 12:46:48 10/24/04
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On October 24, 2004 at 14:40:19, Uri Blass wrote: >On October 24, 2004 at 12:57:06, Michel Langeveld wrote: > >>On October 24, 2004 at 12:22:21, Volker Richey wrote: >> >>>Hi, >>> >>>Swiss Perfect calculates an other Berger value? >>> >>>where is the error? >>> >>>Volker >> >>This method was elected by the players: >> >>"In this tournament a special tie-breaker is in effect to compensate for the >>effect of Swiss-system paring in a tournament with a small number of >>participants. It applies to the players in the lead with an equal number of >>points(P). Only results against mutual opponents and the game among themselves >>count for SB. Buchholz (sum of opponent) points were discarded." >> >>Congrats for Vincent for this Victory! > >I do not understand the method. >What is the meaning of mutual opponents? > >I understand that games against Isichess was not counted when Isichess drew with >the king when the king drew with Diep so I do not think that it is correct to >use that method in the future because games against Isichess are not an obvious >easy win based on the results. > >Uri Suppose you have to play an opponent that scores nothing, and your competitor did play another opponent that may not be easy, but is beatable. Then plain pairing decides who wins the tiebreak, as the program that has to play the weak opponent is without a chance when a tiebreak is used. Remember that the playing strength difference was huge in previous events, and the amount of players is very limited. Regular swiss tiebreak methods are unfair in these cases. Therefor only the SB results against common opponents are used. All other methods have their drawbacks too, and this at least looks like a fair one. Even if it is almost a lottery. Richard.
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