Author: Peter Fendrich
Date: 00:22:57 02/02/05
Go up one level in this thread
On February 01, 2005 at 13:21:54, Thomas Mayer wrote: >Hi Peter, > >On February 01, 2005 at 13:09:56, Peter Fendrich wrote: > >>On February 01, 2005 at 13:01:56, Eiko Bleicher wrote: >> >>>On February 01, 2005 at 12:58:24, Uri Blass wrote: >>> >>>>On February 01, 2005 at 12:20:30, Thomas Mayer wrote: >>>> >>>>>Hi, >>>>> >>>>>just a hypotetic question: >>>>>Let's think that the bishop side has several bishops, all of the same colour. >>>>>The question is now: when not any of the bishops alone can stop the pawn is it >>>>>possible to create a position where they all together can stop it anyway ? >>>>>Or is it sufficent to say that it is a win when the lone pawn was checked in the >>>>>TBs against each bishop and both checks say that it is won ? >>>>> >>>>>I hope you understand what I mean -> I can not really explain it to myself... :) >>>>> >>>>>a possible example: >>>>> >>>>>[D] 3K2b1/7P/8/8/8/8/b2k4/8 w - - 0 1 >>>>> >>>>>without the bishop on b2 this would be of course won and TBs give back a win >>>>>when we check the pawn against both bishops... and of course according to five >>>>>man this position is also won... the question is if it is possible to create a >>>>>position with the above mentioned circomstances which is draw ?! >>>>> >>>>>Greets, Thomas >>>>> >>>>>P.S.: You see, I am working on Quarks endgame... :) >>>> >>>> >>>>I am not sure if this is the example that you look for but 2 bishop can stop the >>>>pawn by Be8 pin when one bishop cannot do it. >>>> >>>>Uri >>>> >>>>[D]k7/5P2/2b3K1/8/b7/8/8/8 b - - 0 1 >>> >>>Hello Uri, >>> >>>now taking the pawn to the f-file is cheating :) I've been trying on h and >>>didn't find such cool things :) >>Here is one. >>[D]8/2K5/8/7P/8/8/6k1/7b w - - 0 1 >>White will win but insert a bishop at f3 with draw. > >your examples are not what I did search... Look at Uri's example. In your case >the f3 bishop would always draw even if the other one is missing. >At the moment I think about examples where white must capture the bishop to win >and can not when it is protected... hm... > >For what that is good for ? Well, at the moment I program internal node >recognizers like Ernst Heinz described... And when it returns a result this have >to be as correct as possible... else the search will get crazy... >It's fun... :) > >Greets, Thomas Ok, each bishop by itself can't draw but together they can. Must it be a- or h-pawn? Otherwise there are many exmples. Here is one with the h-pawn: 8/6K1/4b1b1/5k1P/8/8/8/8 w - - 0 1 This is a draw position. Remove one bishop and it's a win for white. Don't tell me that this is wrong! /Peter
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