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Subject: Re: Assembler Question

Author: James Robertson

Date: 14:20:48 01/27/99

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On January 27, 1999 at 16:45:03, Eugene Nalimov wrote:

>On January 27, 1999 at 15:40:06, James Robertson wrote:
>
>>On January 27, 1999 at 15:00:37, Eugene Nalimov wrote:
>>
>>>On January 27, 1999 at 14:50:59, James Robertson wrote:
>>>
>>>>On January 27, 1999 at 01:32:28, Eugene Nalimov wrote:
>>>>
>>>>>On January 26, 1999 at 22:38:37, James Robertson wrote:
>>>>>
>>>>>>Once again I show my absolute ignorance of assembly with these two questions:
>>>>>>I am trying to acces the 3rd [+ 4th] byte of a register. How? E.g., what is next
>>>>>>after al, ah, ?
>>>>>>How do I pop something off the stack without moving the stack pointer?
>>>>>>
>>>>>>Thanks,
>>>>>>James
>>>>>
>>>>>1. Use shift instruction. E.g.
>>>>>        shr     eax, 16
>>>>>        mov     byte ptr [esi], al
>>>>>   You can also use rotate instruction (it'll not destruct
>>>>>   other bytes):
>>>>>        ror     eax, 16
>>>>>        mov     byte ptr [esi], al
>>>>>        ror     eax, 16
>>>>>   But if I remember it correctly, rotate is worse than shift
>>>>>   (cannot be executed in parallel) on both Pentium and P6 family.
>>>>>2. mov reg32, dword ptr [esp]
>>>>>
>>>>>Eugene
>>>>
>>>>Ok.... that would work. Because I already have stuff stored in ax, and I know
>>>>the exact values I want to put into the 'e' part, I wrote:
>>>>
>>>>or    eax,0xeeee0000
>>>>and   eax,0x0000ffff
>>>>or    eax,0xeeee0000
>>>>
>>>>where eeee=what I want to put in. This seems to work. Are there any problems I
>>>>am missing?
>>>>
>>>>James
>>>
>>>First instruction is unnecessary - one "and" and one "or" will
>>>be enough.
>>>
>>>Also, try to use 32-bit values instead of 16-bit values where
>>>possible. 16-bit operations are more expensive than either 8-bit
>>>or 32-bit.
>>
>>I'm confused. Aren't these 32 bit values?
>>
>>James
>>
>>>
>>>Eugene
>
>Yes, those values are all 32-bit. But you wrote "stuff already
>stored in ax", so I guessed that you made so using instruction
>that operates with 16-bit values. That instruction is usually
>worse than instruction that operates with all 32 bits.

Actually, I have the results of another 32-bit operation in eax. The maximum
value for the result is 63, which is < 16 bits, so I can be sure that the higher
bits of eax are free for other stuff.

>
>One more hint (as you still refusing to read documentation):

That's not true. :) I downloaded several files, but I read slowly.

>if
>you used 16-bit move to load ax, or if you done that using 2
>8-bit moves, and then immediately (less than 20 instructions
>later) try to use eax as a whole, than P6/PII will stall for up
>to 10 CPU clocks before executing those instructions (there are
>some exceptions to that rule - you can read about it Intel
>manuals).

I wonder why Intel decided to do that.....

James

>
>Eugene



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